Question

factorise x^3+13x^2+32x+20​

Answer 1

please mark it as the brainliest answer

Answer 2

Answer:

$(x + 1)(x + 2)(x + 10)$

Step-by-step explanation:

$putting \: x = - 1 \\ {x}^{3} + 13 {x}^{2} + 32x + 20 \\ = {( - 1)}^{3} + 13 { (- 1)}^{2} + 32 \times ( - 1) + 20 \\ - 1 + 13 - 32 + 20 \\ = 32 - 32 \\ = 0 \\ therefore \: (x + 1) \: is \:a \: factor \: of \: given \: polynomial.$

$now \\ {x}^{3} + {13x}^{2} + 32x + 20 \\ = {x}^{3} + {x}^{2} + 12 {x}^{2} + 12x + 20x + 20 \\ = {x}^{2}(x + 1) + 12x(x + 1) + 20(x + 1) \\ = (x + 1)( {x}^{2} + 12x + 20) \\ = (x + 1)( {x}^{2} + 2x + 10x + 20) \\ = (x + 1)( x(x + 2) + 10(x + 2)) \\ = (x + 1)(x + 2)(x + 10) \\ \: \: \: \: \: ans.$