Math, asked by thebrainyone, 1 year ago

factorise x^3+13x^2+32x+20


AdiTi222: are u sure its 13??
wixmatwishwa: (x+1)(x + 2)(x + 10)//////
thebrainyone: yep I'm sure

Answers

Answered by wixmatwishwa
22
=x^3+13x^2+32x+20
value test method for factoring
x= -1;
=(-1)^3 + 13(-1)^2 + 32(-1) + 20
= -1 + 13 - 32  + 20
= 0//
accordingly  >>    x= -1  is factor of  x^3+13x^2+32x+20
a,b,c are constant  not blad 
x^3+13x^2+32x+20 = (x+1)(ax^2 + bx + c)
                                   = ax^3 + bx^2 + cx + ax^2 + bx + c
                                   = ax^3  x^2(b + a) + x(c+b) + c

x^3/      x^2/                                                 x/
a =1     13 = b+a                                       32=c+b
              b=12 (accordingly   a= 1)           c=20

 x^3+13x^2+32x+20  =(x+1)(x^2 + 12x + 20)
x^3+13x^2+32x+20 =(x+1)(x + 2)(x + 10)//////

 

             

thebrainyone: thanks a lot
Answered by oadel2521
0

Answer:

Step-by-step explanation:

sorry i dont know thanks for 5 pts lol

mark as brain list

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