Question

Factorise x^3+13x^2+32x+20 if [x+2] is a factor

Answer 1

Answer:

Taking out the zero of the polynomial of [x+2] :

[x+2] = 0

> x+2 =0

x = -2

putting x= -2 in the given expression x^3+13x^2+32x+20

> -2^3+13*-2^2+32*-2+20

> -8+52-64+20

> -72+72

>0

Hence proved, that [x+2]  is a factor of x^3+13x^2+32x+20

Answer 2

(x+1)(x^2+12x+20)(:for

x=-1 x^3+x^2+12x^2+12x+20x+20

x^2(x+1)+12x(x+1)+20(x+1)

(x+1)(x^2+12x+20)

(x+1)(x^2+10x+2x+20)

(x+1)((x(x+10)+2(x+10)

(x+1)(x+10)(x+2)

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