Question

Factorise x^3+13x^2+3x+26​

Answer 1

I think that your question is incorporated.....

In place of 26 there might be 20....... In that case here's your answers ☺️

The value of x

The value of x 3

The value of x 3 +13x

The value of x 3 +13x 2

The value of x 3 +13x 2 +32x+20 is

The value of x 3 +13x 2 +32x+20 isx

The value of x 3 +13x 2 +32x+20 isx 3

The value of x 3 +13x 2 +32x+20 isx 3 +x

The value of x 3 +13x 2 +32x+20 isx 3 +x 2

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2 (x+1)+12x(x+1)+20(x+1)

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2 (x+1)+12x(x+1)+20(x+1)=(x−1)(x

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2 (x+1)+12x(x+1)+20(x+1)=(x−1)(x 2

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2 (x+1)+12x(x+1)+20(x+1)=(x−1)(x 2 +12x+20)

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2 (x+1)+12x(x+1)+20(x+1)=(x−1)(x 2 +12x+20)=(x−1)(x

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2 (x+1)+12x(x+1)+20(x+1)=(x−1)(x 2 +12x+20)=(x−1)(x 2

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2 (x+1)+12x(x+1)+20(x+1)=(x−1)(x 2 +12x+20)=(x−1)(x 2 +10x+2x+20)

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2 (x+1)+12x(x+1)+20(x+1)=(x−1)(x 2 +12x+20)=(x−1)(x 2 +10x+2x+20)=(x+1)[x(x+10)+2(x+10)]

The value of x 3 +13x 2 +32x+20 isx 3 +x 2 +12x 2 +12x+20x+20=x 2 (x+1)+12x(x+1)+20(x+1)=(x−1)(x 2 +12x+20)=(x−1)(x 2 +10x+2x+20)=(x+1)[x(x+10)+2(x+10)]=(x+1)(x+2)(x+10)

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HOPE IT HELPED YOU ☺️...IF IT DID SO PLEASE MARK ME AS BRAINLIEST ....

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HOPE IT HELPED YOU ☺️...IF IT DID SO PLEASE MARK ME AS BRAINLIEST .......

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