factorise x^3 +2x^2-2
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Given that x3 – 2x2 – x + 2
Grouping the 1st and 3nd terms together and the 2nd and 4th term together:
= x(x2 – 1) – 2(x2 – 1)
x3 – 2x2 – x + 2 = (x2 – 1) (x – 2)
Using the identity: a2 − b2 = (a + b) (a- b)
∴ (x2 – 1) = (x + 1)(x – 1)
= (x – 1) (x + 1) (x- 2)
∴ answer is (x – 1) (x + 1) (x- 2
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