Math, asked by AJadilshameer, 9 months ago

factorise x^3 - 2x^2 - 5x - 6

Answers

Answered by Anonymous
2

Answer:

\begin{lgathered}(x - 1)( {x }^{2} - x - 6) \\ (x - 1)(x {}^{2} - 3x + 2x - 6) \\ (x - 1)(x(x - 3) + 2(x - 3)) \\ (x - 1)(x - 3)(x + 2)\end{lgathered}

(x−1)(x

2

−x−6)

(x−1)(x

2

−3x+2x−6)

(x−1)(x(x−3)+2(x−3))

(x−1)(x−3)(x+2)

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