factorise x^3 - 2x^2 - 5x - 6
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\begin{lgathered}(x - 1)( {x }^{2} - x - 6) \\ (x - 1)(x {}^{2} - 3x + 2x - 6) \\ (x - 1)(x(x - 3) + 2(x - 3)) \\ (x - 1)(x - 3)(x + 2)\end{lgathered}
(x−1)(x
2
−x−6)
(x−1)(x
2
−3x+2x−6)
(x−1)(x(x−3)+2(x−3))
(x−1)(x−3)(x+2)
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