Question

factorise x^3-2x^2-7x+5​

Answer 1

Answer:

$x3-2x2-7x+5  \\ Final \: result \: \\ x3 - 2x2 - 7x + 5 \\ Step \: by \: step \: solution \: : \\ Step \: 1 \: : \\ Equation \: at \: the \: end \: of \: step \: 1 \:: \\ (((x3) - 2x2) - 7x) + 5 \\ Step \: 2 \: : \\ Checking \: for \: a \: perfect \: cube \: : \\   x3-2x2-7x+5  \: is \: not \: a \: perfect \: cube \\ Trying \: to \: factor \: by \: pulling \: out \: : \\ \\ Factoring \: :  x3-2x2-7x+5  \\ Thoughtfully \: split \: the \: expression \: at \: hand \: into \: groups, \: each \: group \: having \: two \: terms \: : \\ Group \: 1:  -7x+5  \: Group \: 2:  \: x3-2x2 </p><p>Pull \: out \: from \: each \: group \: separately : \\ Group \: 1: \: (-7x+5) • \: (1) = \: (7x-5) \: . (-1)</p><p>Group \: 2:  \: (x-2) \: • (x2)</p><p>$

$I \: hope \: this \: will \: helps \: you. \\ Please \: like \: my \: answer.$