Question

factorise: x^3_2x^2-x+2​

Answer 1

Refer to the attachment mate...

Answer 2

Answer:

Step-by-step explanation:

Let x³-2x²-x+2= p(X) =0

X² (x-2 ) -1(x-2) =0

(x² -1 ) (x-2) =0

We know that a²-b² = (a+b)(a-b)

(X+1)(x-1)(x-2) =0

So X+1=0. X-1 =0 x-2=0

X =-1 X = 1. X=2