Question

factorise:x^3-2x^2y+3xy^2-6y^3

Answer 1

this is the answer please see it

Answer 2

Step-by-step explanation:

Given : x

3

−2x

2

y+3xy

2

−6y

3

By taking x

2

as common in the first two term and 3y

2

as common in the second two term

x

3

−2x

2

y+3xy

2

−6y

3

=x

2

(x−2y)+3y

2

(x−2y)

So we get,

x

3

−2x

2

y+3xy

2

−6y

3

=(x−2y)(x

2

+3y

2

)