Question

Factorise
x(3)-3x(2)-9x-5​

Answer 1

Answer:

(x + 1) (x - 5) (x + 1)

Step-by-step explanation:

>> x³ - 3x² - 9x - 5

>> x³ + x² - 4x²- 4x - 5x - 5

>> x²(x + 1) - 4x(x + 1) - 5(x + 1)

>> (x + 1)(x² - 4x - 5)

>> (x + 1)(x² -5x + x - 5)

>> (x + 1) (x - 5) (x + 1)

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Answer 2

Answer:

hey mate

Step-by-step explanation:

here is your answer

Given

x3 - 3 + (2) -9x - 5

by factorising method

p(X) = x³ - 3x² - 9x - 5

Factors of 5 = 1 5 -1 -5

p(1) = 13 - 3 × (1) 2 - 9 × (-1) 5

= 1 - 3 - 9 - 5

= 1 - 17 -16 is not equal to 0

p (-1) = (-1) 3 × 3 × 3 (-1) 2 - 9 × (-1) -5

= -1 -3 + 9 -5 = -9 +9 = 0

p (-1) = 0

(X + 1 ) is factor of p(X)

$\frac{p(x)}{(x + 1)}$

x³ - 3 × 2 - 9 × (-5)/ X +1

X2 - 4 X - 5

x² - 5x + 1 - 5

X ( X - 5) +1 (X - 1 )

(x- 5) (X + 1)

$thanku$