factorise x^3-3x^2-9x-5
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Answer:
( x + 1 ), ( x - 5 ) and ( x + 1 ) are the factors of given polynomial .
Step-by-step explanation:
x^3 - 3x^2 - 9x - 5
= x^3 + x^2 - 4x^2 - 4x - 5x - 5
= x^2 ( x + 1 ) - 4x ( x + 1 ) - 5( x + 1 )
= ( x + 1 ) . ( x^2 - 4x - 5 )
= ( x + 1 ) . ( x^2 - 5x + x - 5 )
= ( x + 1 ) . { x ( x - 5) + 1 ( x - 5 ) }
= ( x + 1 ) . ( x - 5 ) . ( x + 1 )
∴ ( x + 1 ), ( x - 5 ) and ( x + 1 ) are the factors of given polynomial .
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