Question

Factorise x^3 - 3x^2 - 9x - 5.

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Answer 1

x^3 - 3x^2 - 9x - 5--------------equation (1)

x^3 - 3x^2 - 9x - 5=0

Let the value of x be -1

then,

f(x)=x^3-3x^2-9x-5=0

f(-1)= -1-3+9-5=0

So, the value of x=-1

which  is equal to (x+1)

Now using the remainder theorem divide eqn(1) with (x+1) (divide yourself)

On dividing the answer would be= x^2-4x-5

So, (x^2-4x-5)(x+1)

Now we will factorise (x^2-4x-5)

=x^2-4x-x-5

=x(x-4)+(x-5)

So, here I am concluding that your question is incorrect.

Answer 2

Answer:

Step-by-step explanation:

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