factorise x^3+3x^2y+3xy^2+y^3-8
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Answered by
46
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[ x³ + 3x²y + 3xy² + y³ ] - 8
By applying identity of ( x + y )³....
= ( x + y ) ³ - 8
Hope it helps
[ x³ + 3x²y + 3xy² + y³ ] - 8
By applying identity of ( x + y )³....
= ( x + y ) ³ - 8
Hope it helps
Answered by
33
Answer:
(x+y-2)(x²+y²+2xy+2x+2y+4)
Hope this helps. Mark me as brainliest.
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