Factorise x^3+ 3x²y + 3xy² + 2y^3
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Step-by-step explanation:
Hey there !
There is a small error in the question. It is x³ - 3x²y + 3xy² - y³.
So this is of the form of an identity:
( a - b )³ = a³ - 3a²b + 3ab² - b³
Hence we can write the equation as:
x³ - 3x²y + 3xy² - y³ = ( x - y )³
So after factorizing we get, ( x - y )³ .
Hope my answer helped !
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