Question

Factorise:
x^3 + 3x²y + 3xy² +2y^3​

Answer 1

${x}^{3} + 3 {x}^{2} + 2 {y}^{3} = 0$

${x}^{3} + 3 {x}^{2} = - 2 {y}^{3}$

${x}^{2} (x + 3) = - 2 {y}^{3}$

${x}^{2} = \frac{ - 2 {y}^{3} }{x + 3}$

$x = \sqrt{ \frac{ - 2 {y}^{3} }{x + 3} }$

❤ Hope it helped u ❤