Question

factorise x^3+4x^2+x-6​

Answer 1

Answer:

$= (x + 3)(x + 2)(x - 1)$

Step-by-step explanation:

${x}^{3} + 4 {x}^{2} + x - 6$

$= {x}^{3} + 3 {x}^{2} + {x}^{2} + x - 6$

$= {x}^{2} (x + 3) + {x}^{2} + 3x - 2x - 6$

$= {x}^{2} (x + 3) + (x - 2)(x + 3)$

$= (x + 3)( {x}^{2} + x - 2)$

$= (x + 3)( {x}^{2} + 2x - x - 2)$

$= (x + 3)(x + 2)(x - 1)$