Question

factorise x^3 +6x^2 + 12x + 16 ... ans _ (x+4) (x^2 +2x +4)... i did'nt know the solution ...... please ...please...

Answer 1

x^3 + 6x^2 +12x +16.
find the factors of 16 = 1,2,4,8,16.
let x = -4
so,
-64 +96 -48 +16
-112 +112 = 0
so , -4 is a root of the polynomial .
now we have, x = -4
x+4 = 0
so ,(x+4) =0 is a root.
now we have to make the polynomial in the form (x+4).
x^3 + 4x^2 +2x^2 + 8x+ 4x+ 16.
x^2(x+4) + 2x(x+4) + 4(x+4)
(x+4)(x^2+2x+4)...