Question

factorise x^3+6x^2+12x+8​

Answer 1

Answer:

${(x + 2)}^{3}$

this is the ans

Step-by-step explanation:

By hit and trial method -2 is one of the factor

after doing long division we get this eq

${x}^{2} + 4x + 4$

which is square of (x + 2)

Answer 2

Answer:

The answer to this question is

${(x + 2)}^{3} \\ or(x + 2)(x + 2)(x + 2)$

step-by-step explanation:

given equation is

${x}^{3} + 6 {x}^{2} + 12x + 8 \\ now \: we \: solve \: this \: equation \\ {x}^{3} + 6 {x}^{2} + 12x + 8 \\ = {x}^{3} + 3 \times {x}^{2} \times 2 + 3 \times x \times {2}^{2} + {2}^{3} \\ = {(x + 2)}^{3} or(x + 2)(x + 2)(x + 2)$