Question

factorise x^3-6x^2+3x+10 given that (x+1) is a factor.

Answer fast plz.

Answer 1

Given f(x) = x^3 - 6x^2 + 3x + 10.

= > x^3 - 7x^2 + x^2 + 10x - 7x + 10

= > (x + 1)(x^2 - 7x + 10)

= > (x + 1)(x^2 - 2x - 5x + 10)

= > (x + 1)(x(x - 2) - 5(x - 2))

= > (x + 1)(x - 2)(x - 5)


Therefore the factors of x^3 - 6x^2 + 3x + 10 = (x + 1)(x - 2)(x - 5).


Hope this helps!

Answer 2

Brainlist it if it helps you. please