Math, asked by vaishnaviram876, 10 months ago

factorise x^3+6x^2+5-12
please answer soon
I will mark u as brainliest​

Answers

Answered by Anonymous
2

I have one example so, see that example and try to solve you will get ans..!

(

x

+

1

)

(

x

3

)

(

x

4

)

Factors are

x

=

1

,

3

,

4

Explanation:

(

x

3

6

x

2

+

5

x

+

12

)

Since the sum of the coefficients of the terms is zero,

x

+

1

is a factor.

Using synthetic division,

a

a

a

1

a

a

a

a

a

a

1

a

a

a

6

a

a

a

5

a

a

a

12

a

a

a

a

a

a

a

a

a

a

a

a

a

a

1

a

a

a

7

a

12

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

1

a

a

a

7

a

a

a

12

a

a

a

0

(

x

+

1

)

(

x

2

7

x

+

12

)

(

x

+

1

)

(

x

2

3

x

4

x

+

12

)

(

x

+

1

)

(

x

(

x

3

)

4

(

x

3

)

)

(

x

+

1

)

(

x

3

)

(

x

4

)

Factors are

x

=

1

,

3

,

4

Answered by Anonymous
20

Answer:

\huge\underline{\overline{\mid {\bold {\green {☆ansWer☆}}\mid}}}

 {x}^{3}  +  {6x}^{2}  + 5  - 12 = 0

 =  >  {x}^{2}  +  {6x}^{2}  + 5 = 12

 =  >  {x}^{2}  +  {6x}^{2}  = 12 - 5

 =  >  {7x}^{2}  = 7

 =  >  {x}^{2}  =  \frac{7}{7}

 =  >  {x}^{2}  = 1

 =  > x =  \sqrt{1}

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