factorise x^3+6x^2+5-12
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Answers
Answered by
2
I have one example so, see that example and try to solve you will get ans..!
⇒
(
x
+
1
)
(
x
−
3
)
(
x
−
4
)
Factors are
x
=
−
1
,
3
,
4
Explanation:
(
x
3
−
6
x
2
+
5
x
+
12
)
Since the sum of the coefficients of the terms is zero,
x
+
1
is a factor.
Using synthetic division,
a
a
a
−
1
a
a
a
∣
a
a
a
1
a
a
a
−
6
a
a
a
5
a
a
a
12
a
a
a
a
a
a
a
a
a
∣
a
a
a
⏐
↓
a
a
−
1
a
a
a
7
a
−
12
a
a
a
a
a
a
a
a
a
∣
…
…
…
…
…
…
…
…
…
a
a
a
a
a
a
a
a
a
a
a
a
a
a
1
a
a
a
−
7
a
a
a
12
a
a
a
0
⇒
(
x
+
1
)
(
x
2
−
7
x
+
12
)
⇒
(
x
+
1
)
(
x
2
−
3
x
−
4
x
+
12
)
⇒
(
x
+
1
)
(
x
(
x
−
3
)
−
4
(
x
−
3
)
)
⇒
(
x
+
1
)
(
x
−
3
)
(
x
−
4
)
Factors are
x
=
−
1
,
3
,
4
Answered by
20
Answer:
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