Factorise x^3+7x^2+13x+16
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HEY MATE!......
◇ F(x) = x3+7x2+13x+16
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 .
◇ the Leading Coefficient is 1 and the Trailing Constant is 16.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,4 ,8 ,16 .
◇Equation at the end of step 2 : x3 + 7x2 + 13x + 16 = 0 Step 3 :Cubic Equations :
Solve x3+7x2+13x+16 = 0
Future releases of Tiger-Algebra will solve equations of the third degree directly.
Meanwhile we will use the Bisection method to approximate one real solution.
Approximating a root using the Bisection Method :
We now use the Bisection Method to approximate one of the solutions. The Bisection Method is an iterative procedure to approximate a root (Root is another name for a solution of an equation).
The function is F(x) = x3 + 7x2 + 13x + 16
At x= -6.00 F(x) is equal to -26.00
At x= -5.00 F(x) is equal to 1.00
Intuitively we feel, and justly so, that since F(x) is negative on one side of the interval, andpositive on the other side then, somewhere inside this interval, F(x) is zero
◇ The desired approximation of the solution is:
x ≓ -5.054239154
Note, ≓ is the approximation symbol
One solution was found :
x≓-5.054239154
hope it helps u dear......
◇ F(x) = x3+7x2+13x+16
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 .
◇ the Leading Coefficient is 1 and the Trailing Constant is 16.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,4 ,8 ,16 .
◇Equation at the end of step 2 : x3 + 7x2 + 13x + 16 = 0 Step 3 :Cubic Equations :
Solve x3+7x2+13x+16 = 0
Future releases of Tiger-Algebra will solve equations of the third degree directly.
Meanwhile we will use the Bisection method to approximate one real solution.
Approximating a root using the Bisection Method :
We now use the Bisection Method to approximate one of the solutions. The Bisection Method is an iterative procedure to approximate a root (Root is another name for a solution of an equation).
The function is F(x) = x3 + 7x2 + 13x + 16
At x= -6.00 F(x) is equal to -26.00
At x= -5.00 F(x) is equal to 1.00
Intuitively we feel, and justly so, that since F(x) is negative on one side of the interval, andpositive on the other side then, somewhere inside this interval, F(x) is zero
◇ The desired approximation of the solution is:
x ≓ -5.054239154
Note, ≓ is the approximation symbol
One solution was found :
x≓-5.054239154
hope it helps u dear......
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