Math, asked by mariskadsouza559, 5 months ago

factorise
x^3 + 8y^3 + 6xy - 1​

Answers

Answered by sakhareasmita7
0

Answer:

 {x}^{3}  + 8 {y}^{3}  + 6xy - 1 = x \times x \times x  \times 8 \times 8 \times 8 \times y \times y \times y \times 6 \times x \times y \times  - 1

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