Question

factorise: x^3+9x^2+27x+27

Answer 1

$Heya$‼


$x^3+9x^2+27x+27$

Rearranging the given cubic polynomial :

$=x^3+27+9x^2+27x$

$=x^3+3^3+3×3x(x+3)$


$As\:we\:know,$
$(a+b)^3 = a^3+b^3+3ab(a+b)$


$Now, back\:to\:your\:question's\:solution$ :

$=x^3+3^3+3×3x(x+3)$

$(x+3)^3$

Answer 2

Answer:

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Explanation:

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