Question

factorise : x^3-x^2+x+1​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\textbf{\huge{ Answer }}$

$\tt{ x^3 - x^2 + x + 1 = 0 }$

$\tt{ x ( x^2 - x + 1 ) + 1 = 0 }$

$\tt{ x = - 1 }$

Now By Completing Square you get ,

$\tt{ x^2 - x + \frac{1}{4} = - 1 + \frac{1}{4} }$

$\tt{ [ x - \frac{1}{2} ] ^2 = \frac{-3}{4} }$

$\tt{ [ x - \frac{1}{2} ] = ±\sqrt {\frac{-3}{4} } }$

Thus , x = $\tt{ \frac{1}{2}} ± {\sqrt {\frac{-3}{4} }}$

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