factorise x^3 + y^3 + x + y
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Answer:
Hey mate!
(x + y)³ – x – y
= (x + y)³ – (x + y)
= (x + y) [(x + y)² – 1]
[Taking (x + y) common]
= (x + y) [(x + y)² – (1)²]
= (x + y) [(x + y + 1) (x + y – 1)]
= (x + y) (x + y + 1) (x + y – 1)
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Answered by
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(x³ + y³) + x + y
(x + y)(x² + y² - xy) + (x + y)
(x + y)[x² + y² - xy + 1]
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