Question

Factorise x(3x - y) - 5y(3x - y) - z(3x - y)

Answer 1

(X-5y-z)(3x-y) is the answer

Answer 2

Answer:

$\large\boxed{3x^2-16xy+5y^2-3xz+yz}$

Step-by-step explanation:

To solve this problem, first you have to use distributive property.

Given:

x(3x-y)-5y(3x-y)-z(3x-y)

Solutions:

First, expand the form by using with distributive property.

$\large\boxed{\textnormal{Distributive property}}$

$\displaystyle a(b+c)=ab+ac$

$\displaystyle x(3x-y)$

A=X

B=3x

C=Y

Solve.

$\displaystyle x*3x-xy$

$\displaystyle 3xx-xy$

$\displaystyle 3xx=3x^2$

$\displaystyle 3x^2-xy$

Rewrite the problem down.

$\displaystyle 3x^2-xy-5y(3x-y)-z(3x-y)$

Secondly, expand.

$\displaystyle -5y(3x-y)$

Multiply from left to right.

$\displaystyle -5*3=-15$

$\displaystyle -5y*y=5y^2$

$\displaystyle =-15xy+5y^2$

$\displaystyle 3x^2-xy-15xy+5y^2-z(3x-y)$

Then, expand.

$\displaystyle -z(3x-y)=-3xz+yz$

$\displaystyle 3x^2-xy-15xy+5y^2-3xz+yz$

Add numbers from left to right.

Add similar elements from left to right.

$\displaystyle -xy-15xy=-16xy$

$\large\boxed{3x^2-16xy+5y^2-3xz+yz}$

Therefore, the final answer is 3x²-16xy+5y²-3xz+yz.