Question

Factorise: (x-3y)³+ (3y-72)³+ (7z-x)³​

Answer 1

We have

We have(x - 3y) + (3y - 7z) + (7z - x) = 0

We have(x - 3y) + (3y - 7z) + (7z - x) = 0∴ (x - 3y)3 + (3y - 7z)3 + (7z - x)3

We have(x - 3y) + (3y - 7z) + (7z - x) = 0∴ (x - 3y)3 + (3y - 7z)3 + (7z - x)3= 3(x - 3y) (3y - 7z) (7z - x)

Answer 2

Answer:

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Step-by-step explanation:

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