factorise ( x - 3y) + ( 3y - 7z ) cube + ( 7z - x ) cube
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We have to factorize, x - 3y3 + 3y - 7z3 + 7z - x3.Let a = x - 3y ; b = 3y - 7z ; c = 7z - xnow, a + b + c = x - 3y + 3y - 7z + 7z - x = 0Since, a + b + c = 0, then we have, a3 + b3 + c3 = 3abc⇒x - 3y3 + 3y - 7z3 + 7z - x3 = 3 x - 3y 3y - 7z 7z - x
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I want to ask u about ending of sum
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