Factorise : x^4 + 16x^2 - 80
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Answer: Hi mate.....
The factorisation of x^{4} -14x^{2} +1 is (x^{2}+1+4x)(x^{2}+1-4x).
Step-by-step explanation:
We have,
x^{4} -14x^{2} +1
To find, the factorisation of x^{4} -14x^{2} +1=?
∴ (x^{4} +1)-14x^{2}
=((x^{2})^{2} +1^{2} )-14x^{2}
=(x^{2}+1)^{2} -2x^{2}-14x^{2}
[ ∵ a^{2} +b^{2} =(a+b)^{2} -2ab]
=(x^{2}+1)^{2} -16x^{2}
=(x^{2}+1)^{2} -(4x)x^{2}
=(x^{2}+1+4x)(x^{2}+1-4x)
[ ∵ a^{2} -b^{2}=(a+b)(a-b)]
Hence, the factorisation of x^{4} -14x^{2} +1 is (x^{2}+1+4x)(x^{2}+1-4x)
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