Question

Factorise (x+4)^2-5xy-20y-6y^2

Answer 1

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Answer 2

The factor form of given expression is (x - 6 y + 4) (x + y + 4).

Step-by-step explanation:

The given expression is

$(x+4)^2-5xy-20y-6y^2$

It can be rewritten as

$(x+4)^2-5y(x+4)-6y^2$

Substitute x+4=t in the above equation.

$t^2-5yt-6y^2$

$t^2-6yt+yt-6y^2$

$t(t-6y)+y(t-6y)$

$(t-6y)(t+y)$

Substitute t=x+4.

$(x+4-6y)(x+4+y)$

$(x - 6 y + 4) (x + y + 4)$

Therefore, the factor form of given expression is (x - 6 y + 4) (x + y + 4).

#Learn more

Factorise x^2 - 4x + 4.

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