factorise: x^4-3x-2
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Solution:-
given by:-
(x^4+3x−2)=(x^2+ax+b)(x^2+cx+d)(x^4+3x−2)=(x^2+ax+b)(x^2+cx+d)
Expanding the right hand side gives us
a+c= 0
b+d+ac = 0
ad+bc = 3
bd = -2
This gives us the factors to be
(x^2−x+2) and (x^2+x−1)
☆i hope.its help☆
given by:-
(x^4+3x−2)=(x^2+ax+b)(x^2+cx+d)(x^4+3x−2)=(x^2+ax+b)(x^2+cx+d)
Expanding the right hand side gives us
a+c= 0
b+d+ac = 0
ad+bc = 3
bd = -2
This gives us the factors to be
(x^2−x+2) and (x^2+x−1)
☆i hope.its help☆
Jeet1508:
i can not understand
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