Question

Factorise
x^4+4
please solve it​

Answer 1

Answer:

(x^2+2x+2)(x^2-2x+2)

Step-by-step explanation:

(x^2)^2+(2)^2

add and subtract by 4x^2

=(x^2)^2+(2)^2+4x^2-4x^2

=[(x^2)^2+2^2-2*2x^2]-2x^2

=[x^2+2]^2-2x^2

=[x^2+2+2x][x^2+2-2x]

=[x^2+2x=2][x^2-2x+2]

Answer 2

Answer:

x^4 + 4 =(x^2)^2 +2×x^2×2 +(2)^2 -4x^2 =(x^2+2)^2 - (2 x)^2 =(x^2+2+2x) (x^2+2–2x) =(x^2+2x×1^2 + 1) (x^2–2×x+1 +1^2 +1) =[(x+1)^2 -(i)^2] [ (x-1)^2 - (i)^2] =(x+1+i)(x+1-i) (x-1+i) (x-1-i)

: