Math, asked by KeshikaYadav, 1 year ago

Factorise x^4-x^2-12


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Answered by Shardul27
15

  \:  \:  \:  \: {x}^{4} -  {x}^{2} - 12 \\ =  {x}^{4} - 4 {x}^{2} + 3 {x}^{2} - 12 \\  =  {x}^{2}( {x}^{2} - 4) + 3( {x}^{2} - 4) \\  = ( {x}^{2} - 4)( {x}^{2} + 3)   \\  = (x + 2)(x - 2)(x +  \sqrt{3})(x -  \sqrt{3}).



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Answered by Anonymous
6

Answer:

 {x}^{4} -  {x}^{2}  - 12 \\  {x}^{4} - 4 {x}^{2}  + 3 {x}^{2}  - 12 \\  {x}^{2} ( {x}^{2}  - 4) + 3( {x}^{2}  - 4) \\ ( {x}^{2} + 3)( {x }^{2}  - 4)ans

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