Question

factorise x^4-y^4 using indentities​

Answer 1

Answer:(x-y)^4

Step-by-step explanation:

Answer 2

${\huge{\underline{\underline{\sf{\blue{Solution:-}}}}}}$

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

${\large{\underline{\underline{\sf{\orange{We\:know\:that:-}}}}}}$

${a}^{2} - {b}^{2} = (a - b)(a + b)$

${\large{\underline{\underline{\sf{\green{It\:means:-}}}}}}$

${x}^{4} - {y}^{4} = ({x}^{2})^{2} - ({y}^{2})^{2}$

$\large\bf\underline\pink{Using\:Identity:-}$

$( {x}^{2})^{2} - ({y}^{2})^{2} = ( {x}^{2} + {y}^{2})( {x}^{2} - {y}^{2})$

${\boxed{\pink{\tt{Again\:we\:using\:identity:-}}}}$

$\bf\underline{So,}$

$( {x}^{2} - {y}^{2}) = (x - y)(x + y)$

$\small\boxed{\fcolorbox{red}{cyan}{Factors\:of\:given\:expression\:are:-}}$

${x}^{4} - {y}^{4 } = ( {x}^{2} + {y}^{2})(x - y)(x + y)$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

${\large{\underline{\underline{\sf{\red{Additional\:Imformation:-}}}}}}$

$(x + y)^{2} = {x}^{2} + {y}^{2} + 2xy$

$(x - y)^{2} = {x}^{2} + {y}^{2} - 2xy$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━