Question

factorise - x^4y^4 - 256 y^4

Answer 1

Given Equation is x^4y^4 - 256y^4.

Take y^4 common as it exists on both sides.

y^4(x^4 - 256)

= y^4(x^4 - 16^2)

= y^4((x^2 + 16)(x^2 - 16))

= y^4((x^2 + 16)(x+4)(x-4))

= y^4(x^2 + 16)(x+4)(x-4).



Hope this helps!

Answer 2

Answer:

${x}^{4} {y}^{4} - 256 {z}^{4}$

= (x²y²)²-(16z²)²

=(x²y²-16z²)(x²y²+16z²)

=[(xy)²-(4z)²][x²y²+16z²]

=(xy-4z)(xy+4z)(x²y²+16z²)

#hope it helps.....