factorise x^4y^4 - xy
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Answer:
xy(xy-1)(x^2y^2+xy+1)
Step-by-step explanation:
x^4y^4-xy
=xy(x^3y^3-1)
=xy[(xy)^3-(1)^3]
=xy(xy-1)[(xy)^2+xy×1+(1)^2]
xy(xy-1)(x^2y^2+xy+1)
By using identity:(a^3-b^3)=(a-b)(a^2+ab+b^2)
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