Factorise :x^6+5x^3+8
Mohanchandrabhatt:
Hey your answer is here.
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Answered by
73
= x^6 + 5x³ + 8
= x^6 + 5x³ + 8 + x³- x³
= x^6 + 6x³ + 8 - x³
= x^6 + 8 - x³ + 6x³
= ( x² )³ + ( 2 )³ + ( -x )³ - 3(x²)(2)(-x)
Using ( a³ + b³ + c³ - 3abc )
= ( a+ b + c ) ( a² + b² + c² - ab - bc - ca )
= ( x² + 2 - x) [(x²)² + 2² + (-x)² -(x²)(2) -(2)(-x) -(-x)(x²)]
= ( x² + 2 - x ) ( x^4 + 4 + x² - 2x² + 2x + x³)
= ( x² + 2 - x ) ( x^4 + 4 - x² + 2x + x³)
= ( x² + 2 - x ) ( x^4 + x³- x² + 2x + 4 )
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Answered by
3
this is the right answer of x⁶+5x³+8
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