factorise x^6-7x^3+8.
please tell
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Hey buddy!
Your answer is:
(x−2)(x2+2x+4)(x+1)(x2−x+1)
Step-by-step explanation:
Given
x6−7x3−8
=(x3)2−7(x3)−8
=(x3−8)(x3+1)
=(x3−23)(x3+13)
We know
a3+b3=(a+b)(a2−ab+b2)
and a3−b3=(a−b)(a2+ab+b2)
So,
=(x−2)(x2+2x+4)(x+1)(x2−x+1)
Please mark as the brainliest!
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