Question

factorise x^6+8y^6-z^6+6x^2y^2z^2​

Answer 1

Answer:

not understand that question

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Answer 2

Answer:

${x}^{6} + 8 {y}^{6} - {z}^{6} - 6 {x}^{2} {y}^{2} {z}^{2}$

It is similar to

${a}^{3} + {b}^{3} + {c}^{3} - 3abc$

So we can write that

$a = {x}^{2} \\ b = 2 {y}^{2} \\ c = - {z}^{2}$

Therefore

a^3 + b^3 + c^3 - 3abc = (a + b + c) (a^2 + b^2 + c^2 + ab - bc - ac)

Therefore youe answer is...

$({x}^{2} + 2{y}^{2} - {z}^{2} )( {x}^{4} + 4{y}^{4} + {z}^{4} + 2 {x}^{2} {y}^{2} - 2 {y}^{2} {z}^{2} - {x}^{2} {z}^{2})$

Hope this helps...

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