Math, asked by tunukanu, 6 months ago

factorise - (x^8-1)​

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Answered by Anonymous
0

Hope it helps you out.

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Answered by pushkar475933
1

Y Y N.

N QN

X^8 - 1

(X^4)^2 - (1)^2 [^2 - ^2]

=> [(-)(+)]

(X^4-1)(X^4+1)

[(X^2)^2 - (1)^2][(X^2)^2 + (1)^2 + 2×X^2×1 - 2X^2]

[(X^2-1)(X^2+1)][(X^2+1)^2 - (2X^2)^2]

[(X)^2 - (1)^2][(X^2+1+2X^2)(X^2+1-2X^2)]

[(X-1)(X+1)][(X^2+1+2X^2)(X^2+1-2X^2)]

K N.

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