Question

factorise............
x^8-1​

Answer 1

Hi frnd here is your answer.

x^8-1

=(x⁴)² - 1²

=(x⁴ - 1)(x⁴ - 1)

=(x⁴ - 1)((x²)² - 1²)

=(x⁴ + 1)(x² + 1)(x² - 1)

OR

=(x⁴ + 1)(x + 1)(x + 1)

Hope it helps u

Answer 2

Answer:

(x^4 + 1)(x^2 + 1)(x - 1)(x + 1)

Step-by-step explanation:

x^8 - 1

(x^4)^2 - 1^2

(x^4 + 1)(x^4 - 1)

(x^4 + 1){(x^2)^2 - (1)^2}

(x^4 + 1)(x^2 + 1)(x^2 - 1)

(x^4 + 1)(x^2 + 1){(x)^2 - (1)^2}

(x^4 + 1)(x^2 + 1)(x - 1)(x + 1)