Question

factorise x^8-1 = (x^4)2-1^2

Answer 1

Answer:

${x}^{8} - 1$

$(x {}^{4} ) {}^{2} - {1}^{2}$

$( {x}^{4} + 1)( {x}^{4} - 1)$

${(x}^{4} + 1)( {x}^{2} + 1)( {x}^{2} - 1)$

$( {x}^{4} + 1) ({x}^{2} + 1)(x + 1)(x - 1)$

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