factorise: x/8^3+x/27^3
Answers
Answered by
1
Answer:
8
3
+
2
7
3
Step-by-step explanation:
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Answered by
0
Step-by-step explanation:
8(x+y)³-27(x-y)³
8(x+y)³-27(x-y)³=(-x+5y)(19x²-10xy+7y²)
Step-by-step explanation:
Given 8(x+y)³-27(x-y)³
= [2(x+y)]³-[3(x-y)]³
=(2x+2y)³-(3x-3y)³
________________________
We know the algebraic identity:
\boxed {a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})}
a
3
−b
3
=(a−b)(a
2
+ab+b
2
)
_______________________
Here ,
a = 2x+2y, b = 3x-3y
=[2x+2y-(3x-3y)][(2x+2y)²+(2x+2y)(3x-3y)+(3x-3y)²]
=(2x+2y-3x+3y)[4x²+8xy+4y²+6x²-6xy+6xy-6y²+9x²-18xy+9y²]
= (-x+5y)(19x²-10xy+7y²)
Therefore,
8(x+y)³-27(x-y)³
=(-x+5y)(19x²-10xy+7y²)
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