Question

factorise x^8-y^8 by suitable identity​

Answer 1

Using the identity : x^2 - y^2 = (x+y)(x-y)

$= ( {x}^{4} + {y}^{4} )( {x}^{4} - {y}^{4} )$

$= ( {x}^{4} + {y}^{4} )( { {x}^{2} }^{2} - { {y}^{2} }^{2} )$

Using the same identity,

$= ( {x}^{4} + {y}^{4} )( {x}^{2} + {y}^{2} )( {x}^{2} - {y}^{2} )$