factorise x - 8xy^3
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= x (1-8y^3)
Using identity ---- a^3 - b^3= (a-b)(a^2+a×b+b^2),
= x {(1)^3 - (2×y)^3}
= x {1 - 2y} { (1)^2 + 1×2y + (2y)^2 }
= x {1 - 2y} { 1 + 2y + 4(y)^2 } (Answer).
Using identity ---- a^3 - b^3= (a-b)(a^2+a×b+b^2),
= x {(1)^3 - (2×y)^3}
= x {1 - 2y} { (1)^2 + 1×2y + (2y)^2 }
= x {1 - 2y} { 1 + 2y + 4(y)^2 } (Answer).
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