Question

factorise : x^9-9/16

Answer 1

Your Answer :-

The Above is from the Subject Factorization .

WE know that ,

$\boxed{a^{2}- b^{2} = (a+b)(a-b)}$

Same ,

According to Question :-

$x^{9} -\frac{9}{16}$

$(x^{3}) ^{2} - (\frac{3}{4}) ^{2}$

= $(x^{3} - \frac{3}{4})} (x^{3} + \frac{3}{4})}$

^_^ ^_^

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