Math, asked by yogeshagarwal012345, 1 year ago

factorise x cube + 1 by x cube minus 2

Answers

Answered by OmkarT
66
Formula:-

a^3+b^3+c^3 -3.a.b.c=(a+b+c)(a^2+b^2+c^2-a.b-bc-ca)………….(1)

x^3 + 1/x^3 - 2

=x^3+1/x^3+1 -3

=(x)^3+(1/x)^3 +(1)^3–3.x.1/x.1

=(x+1/x+1)(x^2+1/x^2+1^2-x.1/x-1/x.1–1.x)

=(x+1/x+1)(x^2+1/x^2+1–1–1/x-x)

=(x+1/x+1)(x^2+1/x^2–1/x-x) , Answer

Answered by narendrakumar7778
26

here is your answer.

Hope you are able to understand it.

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