Factorise : x cube /216 -8y cube
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Answered by
7
your question can be written as
(x/6)^3-(2y)^3
using (x+y)^3=x^3+y^3+3x^2y+33x^2y+3xy^2
x=x/6,y=2y
put the value in place of the identity you will get the answer
(x/6)^3-(2y)^3
using (x+y)^3=x^3+y^3+3x^2y+33x^2y+3xy^2
x=x/6,y=2y
put the value in place of the identity you will get the answer
Answered by
0
Step-by-step explanation:
very difficult question I also don't know
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