Question

factorise:
x cube - 23x square + 142x - 120​

Answer 1

Answer:

$x {}^{3} - 23x {}^{2} + 142x - 120 = 0 \\ = x {}^{3} - x {}^{2} - 22x {}^{2} + 22x + 120x - 120 = 0 \\ = x {}^{2} (x - 1) - 22x(x - 1) + 120(x - 1) = 0 \\ = (x - 1)(x {}^{2} - 22x + 120) = 0 \\ = (x - 1)(x {}^{2} - 10x - 12x + 120) = 0 \\ = (x - 1)(x(x - 10) - 12(x - 10)) = 0 \\ = (x - 1)(x - 10)(x - 12) = 0 \\ x = 1 \: \: and \: \: 10 \: \: and \: \: 12 \: \: \: answer$

Hey! Mate Here is your solution. Thanks