factorise x cube + 27
Answers
Answered by
47
Given x^3 + 27
We can write 27 as 3×3×3 = 3^3
x^3 + 3^3
(We know that a^3 + b^3 = (a+b)(a^2-ab + b^2)
so here a = x , b=3
subsitute them in the formula
(x-3)(x^2 - 3x +9) are the roots of that equation..
[ we can get one perfect root..i.e., 3 from (x-1)..but we cannot solve the other one..i.e. x^2 -3x +9..so we will stick to that]
We can write 27 as 3×3×3 = 3^3
x^3 + 3^3
(We know that a^3 + b^3 = (a+b)(a^2-ab + b^2)
so here a = x , b=3
subsitute them in the formula
(x-3)(x^2 - 3x +9) are the roots of that equation..
[ we can get one perfect root..i.e., 3 from (x-1)..but we cannot solve the other one..i.e. x^2 -3x +9..so we will stick to that]
Answered by
20
Answer:
hey mate her is your answer
Step-by-step explanation:
pls mark me as brainlist
Attachments:
Similar questions